Frequently Asked Questions...
point charge at the center of a conducting spherical shell?
A point charge Q = 7.80×10-6 C is at the center of a conducting spherical shell of radius R = 6.60 cm. The total charge of the shell is -7.80×10-6 C.
What is the field in the region between the point charge and the shell? (at r= 3.30 cm)
The second part is: What is the field just outside the shell?
Please help. This is due by saturday!
Answer:
For the First part, you only need to worry about the point charge. Everything on the shell cancels per gauss and per Newton's Shell Theorem.
E = Q/(4 π ε r^2)
r = 3.3 cm
&epsilon = 8.85 x 10^-12 C^2/N-m^2
E = 6.44 x10^7 N/C
The field just outside the shell will be:
E = (Q + Q) /4 π ε r^2)
r = 6.6 cm
E = 0
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